Calculation example) T1 to T4 can be calculated as follows. L Speed: V [mm/s] a1 a2 T1 = V/a1 = 300/3000 = 0.1 [s], T3 = V/a2 = 300/3000 = 0.1 [s] Time [s] T = T1 + T2 + T3 + T4 [s] L 0.5 V (T1 + T3) V T1: Acceleration time and T3: Deceleration time can be obtained by the following equation.
Average suction flow rate V x 60 T1 V x 60 T1 Q = Q = + QL T2 = 3 x T1 T2 = 3 x T1 Q : Average suction flow rate /min (ANR) V : Piping capacity () T1 : Arrival time to stable Pv 63% after adsorption (sec.) T2 : Arrival time to stable Pv 95% after adsorption (sec.) QL : Leakage at work adsorption /min (ANR) 2.
Average suction flow rate V x 60 T1 V x 60 T1 Q = Q = + QL T2 = 3 x T1 T2 = 3 x T1 Q : Average suction flow rate /min (ANR) V : Piping capacity () T1 : Arrival time to stable Pv 63% after adsorption (sec.) T2 : Arrival time to stable Pv 95% after adsorption (sec.) QL : Leakage at work adsorption /min (ANR) 2.
Note 2) Splash proof specification is not available for F and T1.
Typ. 7/8 1 5/64 5 8 Hex 3/8 1 3/32 1 7/16 5/8 7/8 11/16 40 1/8 T2 1/2 1/8 T2 1/8 T4 1/8 T6 1/8 T3 1/8 T1 1/8 T5 1/8 T8 1/8 T4-90 1 1/16 Note: Reducing Tees available with other barb combinations #1 7/8 17 32 7 16 7 16 Hex Typ. 27 32 #3 1 3/32 3/4 3/8 Typ. 7/8 9 16 7 16 #2 #4 27/32 3/4 41 1/8 T2 x 3 1/8 RT3 x 1 1/8 T3 x 3 1/8 T1 x 3 1/8 T4 x 3 1/8 RT4 x 2 7/16 7/16 17/32 9/16 19/32
= / 1 Angular deceleration time T3 = / 2 Constant speed time T2 = { 0.5 x x (T1 + T3)}/ Settling time T4 = 0.2 (sec) Speed: [/sec] 1 2 Cycle time T = T1 + T2 + T3 + T4 Selection example Time [s] Angular acceleration time T1 = 420/1,000 = 0.42 sec Angular deceleration time T3 = 420/1,000 = 0.42 sec Constant speed time T2 = {180 0.5 x 420 x (0.42 + 0.42)}/420 = 0.009 sec T1 T2
JOG and constant rate movement, return to origin, test drive and testing of forced output can be performed. 569 B LEC Series Teaching Box/LEC-T1 RoHS How to Order LEC T1 3 J G Enable switch (Option) Enable switch Teaching box Nil None S Equipped with enable switch Cable length [m] 3 3 Interlock switch for jog and test function Stop switch Initial language Stop switch J Japanese E English
L Speed:V [mm/s] Calculation example) T1 to T4 can be calculated as follows. a1 a2 T = T1 + T2 + T3 + T4 [s] Time [s] T1 = V/a1 = 300/3000 = 0.1 [s], T3 = V/a2 = 300/3000 = 0.1 [s] P T1: Acceleration time and T3: Deceleration time can be obtained by the following equation.
JOG and constant rate movement, return to origin, test operation and testing of compulsory output can be performed. 57 Series LEC Teaching Box/LEC-T1 How to Order LEC T1 3 J G Enable switch (Option) Teaching box Enable switch S None Equipped with enable switch Nil Cable length 3 3 m Interlock switch for jog test function Stop switch Initial language J E Japanese English Stop switch G Equipped
JOG and constant rate movement, return to origin, test operation and testing of compulsory output can be performed. 57 Series LEC Teaching Box/LEC-T1 How to Order LEC T1 3 J G Enable switch (Option) Teaching box Enable switch S None Equipped with enable switch Nil Cable length 3 3 m Interlock switch for jog test function Stop switch Initial language J E Japanese English Stop switch G Equipped
Adsorption Response Time with the Formula Adsorption response times T1 and T2 can be obtained through the formulas given below.
-25 NPN output NPN open collector 30V, 80mA, residual voltage: 1V or less ZSE401 T1-26 Vacuum Analog output 1~5V (+ 5%F.S.), load impedance : 1k ZSE401 T1-65 PNP output PNP open collector 80mA ISE4L01 T1-25 Positive Pressure NPN output NPN open collector 30V, 80mA, residual voltage: 1V or less ISE4L01 T1-26 100kPa Analog output 1~5V (+ 5%F.S.), load impedance: 1k ISE4L01 T1-65 (14.5PSI) Type
Determine the mean suction flow: Q r = v x 6 o T1 9 9 0 . s : s : : P o o . g u o.z T 2 = 3 1 o 1 mean suction flow required from ejector (N/min), 0.1 0.2 0.3 0.5 0.7 1 2 3 | 5 7 10 20 30 50 70 100 O T1 i(sec) o1 adsorption response time to 63% to P, (sec), T1 adsorption response time to 95% of P" (sec), T2 1 l lncnnica System Specif ication (continued) 2.
Determine the mean suction flow: Q r = v x 6 o T1 9 9 0 . s : s : : P o o . g u o.z T 2 = 3 1 o 1 mean suction flow required from ejector (N/min), 0.1 0.2 0.3 0.5 0.7 1 2 3 | 5 7 10 20 30 50 70 100 O T1 i(sec) o1 adsorption response time to 63% to P, (sec), T1 adsorption response time to 95% of P" (sec), T2 1 l lncnnic System Specif ication (continued) 2.
T1 = V/a1 = 1000/2500 = 0.4 [s], T1 T2 T3 T4 11LEJS T3 = V/a2 = 1000/2500 = 0.4 [s] L: Stroke [mm](Operating condition) V: Speed [mm/s](Operating condition) a1: Acceleration [mm/s2](Operating condition) a2: Deceleration [mm/s2](Operating condition) T = T1 + T2 + T3 + T4 [s] L 0.5V(T1 + T3) V 25AT2 = T1: Acceleration time and T3: Deceleration time can be obtained by the following equation
Symbol Symbol Applicable tubing size (inch) 2 3 4 5 6 Fitting type Symbol T1 T2 T3 T4 Class No.
-02 Performance/Specifications General specifications LC5-1-T1-02 Part no.
Metric Size L4 Weight (g) AS A2 A1 M L3 L2 L1 d T1 D1 D2 H2 H1 Max.
Connector block assembly (For 9 to 17 stations (T1) terminal block) t-6 SX5000-64-8A SX3000-64-8A M3 x 30 (Matt nickel plated) SX3000-22-2 (M2 x 24) SX5000-57-6 Round head combination screw y Gasket DIN rail SX3000-57-4 VZ1000-11-1u i Refer to page 1-6-77. Note) The numbers t1 to 4 are for 24 VDC. For 12 VDC, suffix -12V to the parts no.