SMC Corporation of America
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Search Results "ZA1071-J16M-FB-M2"

Moment M2max (from (3) of graph MY1C/M2) = 23.0 (Nm) M2 = m2 x g x Y = 6.525 x 9.8 x 29.6 x 103 = 1.89 (Nm) MX m2 Load factor 3 = M2/M2max = 1.89/23.0 = 0.08 MTS M2 MY 5.

moment M2 = WL (mm) Model REAH10 REAH15 REAH20 REAH25 REAHT25 REAHT32 A 15 17.5 19.5 23.5 L L A L M2 0 M1 0 M3 Since there are 2 guides, the guides central axis and the cylinders central axis are the same.

M2 max (from (3) of graph MY1C/M2) = 23.0 (Nm) MY1B M2 = m2 x g x Y = 6.525 x 9.8 x 29.6 x 103 = 1.89 (Nm) m2 Load factor 3 = M2/M2 max = 1.89/23.0 = 0.08 MY1M M2 MY1C 5.

Moment M2max (from (3) of graph MY1C/M2) = 23.0 (Nm) M2 = m2 x g x Y = 6.525 x 9.8 x 29.6 x 103 = 1.89 (Nm) MX m2 Load factor 3 = M2/M2max = 1.89/23.0 = 0.08 MTS M2 MY 5.

max. m1 max. m3 max. m2 max. m1 max.

MY-A32H 74 5.5 73.2 15 8(MAX20) 90 RB2015 6 MY-A40H 74 5.5 73.2 15 9(MAX25) 100 4 Model E EA EB EC EY F FB FC FH FW h S T TT W Shock Absorber No.

0.5 FA FB C Y EH T X M EA EB B + Stroke A + Stroke Note 1) Range within which the rod can move.

M2 8 4.2 Applicable tubing L2 M2 L2 Different Diameter Tee: KQ2T Applicable tubing Applicable tubing O.D.

MY-A32H 74 5.5 73.2 15 8(MAX20) 90 RB2015 6 MY-A40H 74 5.5 73.2 15 9(MAX25) 100 4 Model E EA EB EC EY F FB FC FH FW h S T TT W Shock Absorber No.

L2 L1 xStatic moment Examine M2. Since M1 & M3 are not generated, investigation is unnecessary. M2 = W L1 = 10 0.05 = 0.5 [Nm] 2 = M2/M2 max = 0.5/16 = 0.031 W = 1 [kg] = 10 [N] W M Find the value M2 max when Va = 300 mm/s from Graph (3).

SV1000-67-1A S0700 SV2000-67-1A M2: 0.16 Nm M3: 0.8 Nm M4: 1.4 Nm SV3000-67-1A VQ SV4000-67-1A VQ4 Silencer with One-touch fitting This silencer can be quickly mounted on the manifolds E (exhaust) port.

CX Dimensions Dimensions DM5 x 0.8 Relief port (Vacuum port) -X 20Data FB B + Stroke A + Stroke 5 10 FB B + Stroke A B Bore size (mm) FB A + Stroke 50 stroke or less 66 67.5 109 109 117.5 117.5 121 141 51 stroke or more 97.5 99 114 114 129 129 148 166 20 25 32 40 50 63 80 100 19 20 22 22 23 23 24 29 Other dimensions are the same as standard type. 66 67.5 71.5 78 83 88 102.5 120 A Over 30

Static moment M2 = WL1 = 100.2 = 2 [Nm] 2 = M2/M2 max = 2/16 = 0.125 W = 1 [kg] = 10 [N] W Review M2. Since M1 & M3 are not generated, review is unnecessary. M L1 3. Dynamic moment We = 5 x 10-3WgU = 5 x 10-319.8300 = 15 [N ] Me3 = 1/3We(L2-A) = 1/3150.182 = 0.91 [Nm] 3 = Me3/Me3max = 0.91/10 = 0.091 Me3 Guide central axis We W L2 Review Me3.

Static moment M2 = WL1 = 10 x 0.2 = 2 [Nm] 2 = M2/M2max = 2/16 = 0.125 W = 1 [kg] = 10 [N] W C J G5-S Examine M2. Since M1 & M3 are not generated, investigation is unnecessary. M CV MVGQ L1 CC We = 5 x 103 WgU = 5 x 103 x 1 x 9.8 x 300 = 15 [N] Me3 = 1/3We (L2A) = 1/3 x 15 x 0.182 = 0.91 [Nm] 3 = Me3/Me3max = 0.91/10 = 0.091 3.

Static moment M2 = WL1 = 10 0.2 = 2 [Nm] 2 = M2/M2max = 2/16 = 0.125 W = 1 [kg] = 10 [N] W REA Examine M2. Since M1 & M3 are not generated, investigation is unnecessary. REB M REC L1 CY 3. Dynamic moment We = 5 x 103 WgU = 5 x 103 1 9.8 500 = 25 [N] Me3 = 1/3We (L2 A) = 1/3 25 0.182 = 1.52 [Nm] 3 = Me3/Me3max = 1.52/6 = 0.25 CX Me3 Examine Me3.

moment M2 = WL (mm) Model REAH10 REAH15 REAH20 REAH25 REAHT25 REAHT32 A 15 17.5 19.5 23.5 L L A L M2 0 M1 0 M3 Since there are 2 guides, the guides central axis and the cylinders central axis are the same.

Find the inertial moment B for the rotation of shaft (B). 3 + m2 a22 + K (Example) When shape of m2 is a sphere, refer to 7, and K = m2 2r2 2.

Find the inertial moment B for the rotation of shaft (B). 3 + m2 a22 + K (Example) When shape of m2 is a sphere, refer to 7, and K = m2 2r2 2.