SMC Corporation of America
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demand = 1000 n/min (N)VBA2, (N)VBA4 C H A R G E C H A R A C T E R I S T I C S NVBA1 C H A R G E C H A R A C T E R I S T I C S Charging time for 10l t(s) Charging time for 10l t(s) Pressure increase ratio (P2/P1) Pressure increase ratio (P2/P1) These graphs illustrate the time required to inrease pressure in a closed tank e.g.

How to Find the Flow Rate (At air temperature of 20C) Choke flow: (P2 + 0.1)/(P1 + 0.1) ) 0.5 293 273 + t Q = 120 x S x (P1 + 0.1) x Subsonic flow: when (P2 + 0.1)/(P1 + 0.1) > 0.5 Q = 240 x S x (P1 P2)(P2 + 0.1) x 293 273 + t Q: Air flow rate [ /min (ANR)] S: Effective area (mm2) P1: Upstream pressure [MPa] P2: Downstream pressure [MPa] t: Air temperature [C] Note 1) Formulas above are

Subsonic flow at P1 + 0.1013 < 1.89 (P2 + 0.1013) Q = 226S P (P2 + 0.1013) Sonic flow of P1 + 0.1013 1.89 (P2 + 0.1013) Q = 113S (P1 + 0.1013) VER2000 Q: Air flow rate [/min (ANR)] S: Effective area [mm2] P: Amount of pressure drop P1 P2 [MPa] P1: Upstream pressure [MPa] P2: Downstream pressure [MPa] Cylinder stroke (st/mm) Correction for varying air temperatures: Square the coefficient

Tighten the orifice again and connect the pilot piping to port P1 using an M5 fitting.

Q=226S P(P2+0.1013) Sonic flow : P1+0.10131.89(P2+0.1013) Q=113S(P1+0.1013) Q : Flow rate [ /min(ANR)] S : Effective area (mm2) P : Pressure differential (P1-P2) [MPa] P1 : Upstream pressure [MPa] P2 : Downstream pressure [MPa] When the air temperature is different, multiply the flow rate calculated with the above formula by the following coefficient for compensation. -20 1.08 -10 0 10 30

How to Find the Flow Rate (at air temperature of 20C) Subsonic flow when P1 + 0.1013 < 1.89 (P2 + 0.1013) Q = 226S P(P2 + 0.1013) Sonic flow when P1 +0.1013 1.89 (P2 + 0.1013) Q = 113S (P1 + 0.1013) Q: Air flow rate [l/min(ANR)] S: Effective sectional area (mm) P: Differential pressure (P1-P2) [MPa] P1: Upstream pressure [MPa] P2: Downstream pressure [MPa] Correction for different air temperatures

How to Find the Flow Rate (at air temperature of 20C) Subsonic flow when P1 + 0.1013 < 1.89 (P2 + 0.1013) Q = 226S P(P2 + 0.1013) Sonic flow when P1 +0.1013 1.89 (P2 + 0.1013) Q = 113S (P1 + 0.1013) Q: Air flow rate [l/min(ANR)] S: Effective area (mm) P: Pressure drop (P1-P2) [MPa] P1: Upstream pressure [MPa] P2: Downstream pressure [MPa] Maintenance Correction for different air temperatures

How to Find the Flow Rate (at air temperature of 20C) Subsonic flow when P1 + 0.1013 < 1.89 (P2 + 0.1013) Q = 226S P(P2 + 0.1013) Sonic flow when P1 + 0.1013 1.89 (P2 + 0.1013) Q = 113S (P1 + 0.1013) Q: Air flow rate [l/min (ANR)] S: Effective area (mm) P: Differential pressure (P1-P2) [MPa] P1: Upstream pressure [MPa] P2: Downstream pressure [MPa] Correction for different air temperatures

Maximum load current: 30mA The NPN and PNP digital monitor outputs can be set to function in one of three different ways: comparator mode hysteresis mode self-diagnostic mode when P1P1>=P2 when P1=P2=0 The output is on whenever the outlet pressure is greater than P1 but less than P2. The output comes on once the outlet pressure reaches P1.

Subsonic flow at P1 + 0.1013 < 1.89 (P2 + 0.1013) Q = 226S P (P2 + 0.1013) Sonic flow of P1 + 0.1013 1.89 (P2 + 0.1013) Q = 113S (P1 + 0.1013) Q: Air flow rate [l/min (ANR)] S: Effective area [mm2] P: Amount of pressure drop P1 P2 [MPa] P1: Upstream pressure [MPa] P2: Downstream pressure [MPa] Cylinder stroke (st/mm) Applicable area Unapplicable area Outlet pressure (MPa) Outlet pressure

Cylinder pressure (P2) VQC Specifications SQ 0.8 MPa 0.15 MPa 5 to 50C 0.60 dm3/(sbar) 180 CPM Max. operating pressure Min. operating pressure SUP side pressure (P1) Ambient and fluid temperature Flow characteristics: C Max. operating frequency VQ0 To CYL port VVQ1000-FPG-02 1 set VQ1000-FPG-C6M5-D 2 pcs.

Pmax Vacuum pressure P1 1. When ejector suction port is covered and made airtight, suction flow becomes zero and vacuum pressure is at maximum value (Pmax). 2. When suction port is opened gradually, air can flow through, (air leakage), suction flow increases, but vacuum pressure decreases. (condition P1 and Q1) 3.

Tighten the fixed orifice again and connect the pilot piping to port P1 using an M5 fitting.

Using a flat head screwdriver, remove the fixed orifice from port P1. 2. Install the fixed orifice facing in the opposite direction (external pilot). Install it carefully to prevent damage to the O-ring. 3. Tighten the fixed orifice again and connect the pi lot piping to port P1 using an M5 fitting.

Selecting conditions: Nozzle diameter: 0.3 P1: 0 [kPa] P2: 20 [kPa] The flow rate will be 0.7 to 0.8 [l/min] based on the graph. Select the PFMV510-1.

Q=240S P(P1+0.100) Subsonic flow when (P2+0.100)/ (P1+0.100)>0.5 Sonic flow when (P2+0.100)/ (P1+0.100)0.5 Q: Air flow ratedm 3 /min(ANR) Q=120S (P1+0.100) 2 ) P: Differential pressure P1P2MPa P1: Upstream pressureMPa P2: Downstream pressureMPa Correction for different air temperatures Multiply the flow rate calculated with the about formula by a coefficient from the table below.

Maximum load current: 30mA The NPN and PNP digital monitor outputs can be set to function in one of three different ways: comparator mode hysteresis mode self-diagnostic mode when P1P1>=P2 when P1=P2=0 The output is on whenever the outlet pressure is greater than P1 but less than P2. The output comes on once the outlet pressure reaches P1.

(Nm) ML2B/M1 (Pitch moment) ML2B/M2 (Roll moment) ML2B/M3 (Yaw moment) Pitch moment M1/M1e 10 20 40 Roll moment M2 1.2 2.4 4.8 Yaw moment M3/M3e 3.0 6.0 12 MI W S 40 Model 20 30 YES 20 5 4 3 10 ML2B25 ML2B32 ML2B40 CEP1 If speed or load changes, stopping time may vary and positioning accuracy may be compromised.

Pitch moment Roll moment NO NO M1 = W1 x L1 M2 = W3 x L3 L1 L3 YES The product is operatable at 14.5 mT or less magnetic field ? Is there any influence from magnetic fields ? (Refer to Caution on Handling on pages 706 and 707.) M1 M2 YES W1 NO W3 NO M1 = W4 x L3 M2 = W1 x L2 Do not use it since it will result in a miscount. L3 L2 YES Is water, oil, burr or dust present?

(Moment of inertia) 2 = m2 + m2 L2 D2 8 4.6 x 104 (Calculation example) Cylinder bore size 32 A = 0.07 m, B = 0.02 m, S = 0.012 m, L = 0.045 m, D = 0.02 m m1 = 0.16 kg, m2 = 0.15 kg 1 = 0.16 x + 0.16 x = 1.6 x 104 kgm2 0.012 0.072 + 0.022 2 0.07 2 1.0 x 104 12 120 200 10 100 1000 2 = 0.15 x + 0.15 x 0.0452 = 3.0 x 104 kgm2 0.022 Maximum piston speed [mm/s] 8 Calculation Example (32, clamp