The required time to increase tank pressure from 0.8MPa to 1.0MPa at 0.5MPa supply pressure is calculated as follows 0.8 0.5 = = 1.6 P2 P1 P2 P1 1.0 0.5 = =2.0 1.0 0.5 = = 2.0 P2 P1 P2 P1 1.5 0.5 = = 3.0 0.8 0.5 = = 1.6 P2 P1 P2 P1 1.0 0.5 = = 2.0 With the pressure increase ratio from 1.6 to 2.0, the time of 6516=49 sec.(t) is given for 10l tank by the graph.
Remove the gauge and balance the bridge circuit (P1 = P2) by adjusting the variable orifice (S3) via the adjustment knob. By moving the work piece away from the nozzle (S4) a pressure differential (P1 P2) is created. As soon as the work piece is moved within the detection range of the AirCatch Sensor the back pressure P2 increases.
This is the same concept representing the easy to run through as sonic conductance C (effective area). (3) Formula of flow rate When P2 + 0.1 0.5, choked flow P1 + 0.1 293 Q = 120 x S (P1 + 0.1) (3) 273 + t When P2 + 0.1 > 0.5, subsonic flow P1 + 0.1 293 Q = 240 x S (P2 + 0.1) (P1 P2) (4) 273 + t Conversion with sonic conductance C: S = 5.0 x C(5) Q :Air flow rate[dm3/min(ANR)], dm3 (
This is the same concept representing the easy to run through as sonic conductance C. (3) Formula for flow rate When P2 + 0.1 0.5, choked flow P1 + 0.1 293 Q = 120 x S (P1 + 0.1) (3) 273 + t When P2 + 0.1 > 0.5, subsonic flow P1 + 0.1 293 Q = 240 x S (P2 + 0.1) (P1 P2) (4) 273 + t Conversion with sonic conductance C: S = 5.0 x C(5) Q : Air flow rate[dm3/min(ANR)], dm3 (cubic decimeter
G Drain Drain P2 (Pressure gauge port size) Applicable model AC20D-A AC30D-A to AC40D-06-A With drain guide Drain cock with barb fitting With drain guide With auto drain (N.O.
The value of the effective area S, like that of sonic conductance C, expresses the ease of flow. (3) Formula for flow rate When P2 + 0.1 0.5, choked flow P1 + 0.1 293 Q = 120 x S (P1 + 0.1) (3) 273 + T When P2 + 0.1 > 0.5, subsonic flow P1 + 0.1 293 Q = 240 x S (P2 + 0.1) (P1 P2) (4) 273 + T Conversion with sonic conductance C: S = 5.0 x C(5) Q : Air flow rate [L/min (ANR)] S : Effective
The valve element for the C.O. type, which has no return spring, is in an arbitrary position when air is exhausted through the ports P1 and P2. When pressurized air enters the port P1 (exhaust from the port P2), the valve element opens, and it closes when pressurized air enters the port P2 (exhaust from the port P1).
This is the same concept representing the easy to run through as sonic conductance C. (3) Formula for flow rate When P2 + 0.1 0.5, choked flow P1 + 0.1 293 Q = 120 x S (P1 + 0.1) (3) 273 + t When P2 + 0.1 > 0.5, subsonic flow P1 + 0.1 293 Q = 240 x S (P2 + 0.1) (P1 P2) (4) 273 + t Conversion with sonic conductance C: S = 5.0 x C(5) Q : Air flow rate[dm3/min(ANR)], dm3 (cubic decimeter)
VBA4 The required time to increase tank pressure from 0.8 MPa to 1.0 MPa at 0.5 MPa supply pressure is calculated as follows. 1.0 0.5 = = 2.0 P2 P1 P2 P1 P2 P1 0.8 0.5 = = 1.6 P2 P1 1.5 0.5 = = 3.0 1.0 0.5 = = 2.0 0.8 0.5 = = 1.6 P2 P1 P2 P1 With the pressure increase ratio from 1.6 to 2.0, the time of 65 16 = 49 sec. (t) is given for 10 l tank by the graph.
This is the same concept representing the easy to run through as sonic conductance C. (3) Formula for flow rate P1 + 0.1 P2 + 0.1 When 0.5, choked flow Q = 120 x S (P1 + 0.1) . .(3) 273 + t 293 P1 + 0.1 P2 + 0.1 When > 0.5, subsonic flow Q = 240 x S (P2 + 0.1) (P1 P2) . .(4) Conversion with sonic conductance C: S = 5.0 x C . .(5) Q : Air flow rate [dm3/min(ANR)], dm3 (cubic decimeter) of
This is the same concept representing the easy to run through as sonic conductance C. (3) Formula for flow rate When P2 + 0.1 0.5, choked flow P1 + 0.1 293 Q = 120 x S (P1 + 0.1) (3) 273 + t When P2 + 0.1 > 0.5, subsonic flow P1 + 0.1 293 Q = 240 x S (P2 + 0.1) (P1 P2) (4) 273 + t Conversion with sonic conductance C: S = 5.0 x C(5) Q : Air flow rate[dm3/min(ANR)], dm3 (cubic decimeter
The value of the effective area S, like that of sonic conductance C, expresses the ease of flow. (3) Formula for flow rate When P2 + 0.1 0.5, choked flow P1 + 0.1 293 Q = 120 x S (P1 + 0.1) (3) 273 + t When P2 + 0.1 > 0.5, subsonic flow P1 + 0.1 293 Q = 240 x S (P2 + 0.1) (P1 P2) (4) 273 + t Conversion with sonic conductance C: S = 5.0 x C(5) Q : Air flow rate [dm3/min (ANR)], dm3
This is the same concept representing the easy to run through as sonic conductance C. (3) Formula for flow rate P1 + 0.1 P2 + 0.1 When 0.5, choked flow 293 Q = 120 x S (P1 + 0.1) .(3) 273 + t P1 + 0.1 P2 + 0.1 When > 0.5, subsonic flow 293 Q = 240 x S (P2 + 0.1) (P1 P2) .(4) 273 + t Conversion with sonic conductance C: S = 5.0 x C .(5) Q : Air flow rate [dm3/min(ANR)], dm3 (cubic decimeter
When P2 + 0.1 b, choked flow P1 + 0.1 293 Q = 600 x C (P1 + 0.1) (1) 273 + t When P2 + 0.1 > b, subsonic flow P1 + 0.1 2 P2 + 0.1 b P1 + 0.1 Q = 600 x C (P1 + 0.1) 1 (2) 1 b 293 273 + t Q : Air flow rate [dm3/min (ANR)], dm3 (Cubic decimeter) of SI unit are also allowed to described by l (liter). 1 dm3 = 1 l .
This is the same concept representing the easy to run through as sonic conductance C (effective area). (3) Formula of flow rate When P2 + 0.1 0.5, choked flow P1 + 0.1 293 Q = 120 x S (P1 + 0.1) (3) 273 + t When P2 + 0.1 > 0.5, subsonic flow P1 + 0.1 293 Q = 240 x S (P2 + 0.1) (P1 P2) (4) 273 + t Conversion with sonic conductance C: S = 5.0 x C(5) Q :Air flow rate[dm3/min(ANR)], dm3 (
VXS VXS VXB VXE (3) Formula for flow rate When P2 + 0.1 0.5, choked flow P1 + 0.1 293 Q = 120 x S (P1 + 0.1) (3) 273 + T When P2 + 0.1 > 0.5, subsonic flow P1 + 0.1 293 Q = 240 x S (P2 + 0.1) (P1 P2) (4) 273 + T Conversion with sonic conductance C: VXP VXR VXH VXF VX3 VXA S = 5.0 x C(5) Q : Air flow rate[L/min(ANR)] S : Effective area [mm2] P1 : Upstream pressure [MPa] P2 : Downstream
This is the same concept representing the easy to run through as sonic conductance C (effective area). (3) Formula of flow rate When P2 + 0.1 0.5, choked flow P1 + 0.1 293 Q = 120 x S (P1 + 0.1) (3) 273 + t When P2 + 0.1 > 0.5, subsonic flow P1 + 0.1 293 Q = 240 x S (P2 + 0.1) (P1 P2) (4) 273 + t Conversion with sonic conductance C: S = 5.0 x C(5) Q : Air flow rate[dm3/min(ANR)], dm3 (
AC200230V AC100120V 40 M5 3.24[Nm] M5 3.24[Nm] 6 AC100120V AC200230V AC100120V AC200230V L1 L1 PE PE L2 2-M5 2-M5 L2 L3 CNP1 CNP1 N N P1 P1 M4 1.2[Nm] P2 P2 M4 1.2[Nm] P P C C CNP2 D CNP2 D L11 L11 L21 L21 U U CNP3 V CNP3 V W W 9 2 9 (2) LECSS-S8 [mm] 5 40 6 6 6 (80) (170) 6 6 () CN4 CN2L CN2 CN1B CN1A CN3 CN5 CNP1 L1 L2 L3 N P1 P2 P C D L11 L21 U V W L1 L2 () L3 N P1 CNP2 P2
Clearance For Maintenance W E G A AC-B AA M J N F (2) P1 (Port Size) C B Q Q V IN OUT K P2 (Gauge Port Size) Bracket and Relief Valve (Optional) U Min.
Example: The figure below is based on the condition of set values as P1 = 40 [kPa] and P2 = 20 [kPa].