SMC Corporation of America
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Search Results "KQB2L04-G01-F"

, 60C (F and FS type only)] IDF IDU IDF FS Refer to SMC website for details.

Type: [Fitting] One-Touch / Screw, Fitting Type: Screw Mount Direction, Tube Size 1(φ): 4, Threaded Adapter Shape: [Elbows] Elbow, Body Material: [Brass] Brass (Electroless nickel plating), Application: Standard/Mini, Thread Portion Material: [Brass] Brass + Electroless Nickel Plating, Packing, Material of O-Ring: [Fluororubber] Fluorine Rubber, Threaded Adapter Elbow Shape: [Universal Elbows

[mm] Weight [g] Nylon Urethane 4 1/8 KQ2F04-G01 14 7.9 24.7 9.5 13.3 5.6 4 3 12.4 1/4 KQ2F04-G02 17 7.9 30.1 13.9 13.3 5.6 4 3 21.3 6 1/8 KQ2F06-G01 14 9.9 24.3 9.5 13.3 13.1 10.4 4.5 12.6 1/4 KQ2F06-G02 17 9.9 29.6 13.9 13.3 13.1 10.4 4.5 21.4 3/8 KQ2F06-G03 21 9.9 31.1 13.7 13.3 13.1 10.4 4.5 29.6 Applicable tubing Connection thread H 8 1/8 KQ2F08-G01 14 13 24.7 9.5 14.2 26.1 18 6 15.1

AS-F D3 D1 Y TMH ASD M L3 AS L5 A AS-FE L4 D2 KE AS-FG AS-FP L2 L1 T H (Width across flats) AS-FM AS-D Metric Size [mm] AS-T Model d T H D1 D2 D3 L1 L2 L3 L4 L5 A M W1 Y Weight [g] Unlocked Locked Unlocked Locked AS231FS1-G01-23 3.2 ASP 14 AS231FS1-G01-04 4 8.2 13.9 25.1 15 AS231FS1-G01-06 6 10.4 26.2 20.4 38.5 15 AS231FS1-G01-08 8 13.2 10.2 16.4 30.1 21.5 39.7 14.2 16 AS231FS1-G02-04 4 7.2

TMH L4 L3 M ASD AS D2 AS-FE L5 A KE AS-FG AS-FG AS-FP T L2 L1 AS-FM H (Width across flats) AS-D Metric Size [mm] AS-T Model d T H D1 D2 D3 L1 L2 L3 L4 L5 A M Weight [g] Unlocked Locked Unlocked Locked AS23l1FG-G01-23A 3.2 ASP 10 AS23l1FG-G01-04A 4 8.2 13.9 25.1 10 AS23l1FG-G01-06A 6 10.4 26.2 20.4 38.5 11 AS23l1FG-G01-08A 8 13.2 10.2 16.4 30.1 21.5 39.7 14.2 12 AS23l1FG-G02-04A 4 7.2 13.3

D3 D1 Y TMH ASD M L3 AS L5 A AS-FE L4 D2 KE AS-FG AS-FG AS-FP L2 L1 T H (Width across flats) AS-FM AS-D Metric Size [mm] AS-T Model d T H D1 D2 D3 L1 L2 L3 L4 L5 A M W1 Y Weight [g] Unlocked Locked Unlocked Locked AS231FSG1-G01-23 3.2 ASP 14 AS231FSG1-G01-04 4 8.2 13.9 25.1 15 AS231FSG1-G01-06 6 10.4 26.2 20.4 38.5 15 AS231FSG1-G01-08 8 13.2 10.2 16.4 30.1 21.5 39.7 14.2 16 AS231FSG1-G02-

) the conditions under which the workpiece will not drop are n x F > mg and therefore, F F mg F > n x m x g With a as the safety margin, F is determined as follows: a x mg F = n x MHZ MHF Multiples of Gripping Force by Workpiece Mass MHL Number of fingers: When n = 2 SMC performs calculations allowing for impacts which occur during normal transfer, etc., using a safety margin of a = 4.

N] F=-q x PA+w x PC F=q x PA+(e-q) x PC F=-q x PA+r x PB+(w-e) x PC F=q x PA q, w and e are piston areas.

AMF150C AMF-EL150 AMF-EL150-F AMF250C AMF-EL250 AMF-EL250-F AMF350C AMF-EL350 AMF-EL350-F AMF550C AMF-EL550 AMF-EL550-F AMF650 AMF-EL650 AMF850 AMF-EL850 Except option F For option F Element assembly Glass fiber, others AMF-EL450 AMF-EL450-F 4 Industrial Filters Replacement Procedure Actuators Modular F.R.L.

Calculation of applied lateral load The lateral load F equals the total load of the workpiece. Thus, F= 5 x 0.05 x 9.8 = 2.5 (N) 1. Calculation of applied lateral load F F = N m g (N) = 0.2 x 10 x 0.1 x 9.8 = 2.1 (N) CC 70 Lateral load F (N) RB 60 0.4 MPa 50 J 40 2.

Calculation of applied lateral load F The lateral load F equals the coefficient between the work piece and the conveyor. Thus, from the total amount of the work piece and coefficient of friction, F = x m g (N) 1. Calculation of applied lateral load The lateral load F equals the total load of the work piece. Thus, F = x m g (N) 2.

Calculation of applied lateral load The lateral load F equals the total load of the workpiece. Thus, F= 5 x 0.05 x 9.8 = 2.5 (N) 1. Calculation of applied lateral load F F = N m g (N) = 0.2 x 10 x 0.1 x 9.8 = 2.1 (N) CC 70 Lateral load F (N) RB 60 0.4 MPa 50 J 40 2.

Replacement part/Grease pack part no.: MH-G01 (30 g) MHKL2 Replacement Parts Description MHKL2-12 MHKL2-16 MHKL2-20 MHKL2-25 Main parts wyu !6!7!8!

Calculation of applied lateral load The lateral load F equals the total load of the work piece. Thus, F = x m g (N) 1. Calculation of applied lateral load F The lateral load F equals the coefficient between the work piece and the conveyor. Thus, from the total amount of the work piece and coefficient of friction, F = x m g (N) 2.