Series VQ1000/2000 10- 21- 5 Port Solenoid Valve 1021-VQ2400 1021-VQ2301 1021-VQ2401 (B) 2 (A) 4 (B) 2 (A) 4 (B) 2 (A) 4 (B) 2 (A) 4 3 (R2) 1 (P) 5 (R1) 3 (R2) 1 (P) 5 (R1) 3 (R2) 1 (P) 5 (R1) 3 (R2) 1 (P) 5 (R1) r r 1021-VQ2500 1021-VQ2501 (B) 2 (A) 4 (B) 2 (A) 4 3 (R2) 1 (P) 5 (R1) 3 (R2) 1 (P) 5 (R1) Component Parts Component Parts No.
When the number of generated alarms exceeds the maximum alarm output of each mode, it is deleted from the history in order of the alarm code generated in the past Ex) When the alarm is generated in order of (1)(5) 7 to 0 Alarm 1 Alarm 1 7 F to 8 Alarm 2 Alarm 2 Alarm 1 (latest) (1) 7 to 0 Alarm 3 (2) (3) (4) (5) Alarm 2 0 (1) (2) (3) (4) Alarm 3 0 0 (1) (2) (3) 8 Alarm 4 0 0 0 (1) (2) (1)
1 !1 o !5 (Short shaft side) For size 40 (Short shaft side) (Short shaft side) Component Parts Description Material Note Description Material Note No. !0 !1 !2 !3 !4 !5 !6 !7 !
The Alarm Display screen is displayed if error occurs in this system. Table 5-2 Model Indication Screen No. Item Descriptions 1 System model 2 System revision No. 5.3.2 Status screen 1 1 2 3 Figure 5-4 Status Screen 1 Table 5-3 Status Screen 1 No.
From the formula on the front matter 18, the average suction flow rate Q1 is as follows: Q1 = (1/2 to 1/3) x Ejectors max. suction flow rate = (1/2 to 1/3) x 5 = 2.5 to 1.7 L/min (2) Next, find the maximum flow rate Q2 of the piping. The conductance C is 0.22 from the Selection Graph (3).
From the formula on the front matter 18, the average suction flow rate Q1 is as follows: Q1 = (1/2 to 1/3) x Ejectors max. suction flow rate = (1/2 to 1/3) x 5 = 2.5 to 1.7 L/min (2) Next, find the maximum flow rate Q2 of the piping. The conductance C is 0.22 from the Selection Graph (3).
From the formula on the front matter 18, the average suction flow rate Q1 is as follows: Q1 = (1/2 to 1/3) x Ejectors max. suction flow rate = (1/2 to 1/3) x 5 = 2.5 to 1.7 L/min (2) Next, find the maximum flow rate Q2 of the piping. The conductance C is 0.22 from the Selection Graph (3).
From the formula on the front matter 18, the average suction flow rate Q1 is as follows: Q1 = (1/2 to 1/3) x Ejectors max. suction flow rate = (1/2 to 1/3) x 5 = 2.5 to 1.7 L/min (2) Next, find the maximum flow rate Q2 of the piping. The conductance C is 0.22 from the Selection Graph (3).
1 !2 !3 !4 !5 !6 !7 No. q w e r t y u i o !
0.043 Note 1) Front boss mount is optional specification.
: 1/8, Pressure gauge type: G43 *4 Only metal bowl 2 is available. *5 The only difference from the standard specifications is the spring for the regulator.
2 3 4 5 Transfer load m (kg) 30 L2 20 L2 (mm) Mer m Rolling Yawing 10 L2 0 1 2 3 4 5 Mer Transfer load m (kg) m 30 a = 1000 a = 500 20 L3 (mm) a = 2000 L3 10 m Mey a 0 1 2 3 4 5 Transfer load m (kg) Refer to page 145 for deflection data. 88 89 Courtesy of Steven Engineering, Inc.-230 Ryan Way, South San Francisco, CA 94080-6370-Main Office: (650) 588-9200-Outside Local Area: (800) 258-9200
However, the maximum number of stations is 11 + stations required for mounting. 2 1 2. How to order applicable valves Stations VQ 5 1 0 0 Y 5 7 B W D side 3 2 4 6 1 5 Note) Stations are counted starting from station 1 on the D side. Body type 4.
System 4 1: Diagnosis of SI unit is generated. 5 1: Diagnosis of IO-Link master unit is generated. 6-7 Reserved 0 1: There is an error in unit 0. 1 1: There is an error in unit 1. 2 1: There is an error in unit 2. 3 1: There is an error in unit 3. 4 Unit 4 1: There is an error in unit 4. 5 1: There is an error in unit 5. 6 1: There is an error in unit 6. 7 1: There is an error in unit 7.
VS VQ 0 5 1 0 1 Y VS7 (Example) Enclosure Series With lead wire kit/cable (3m) VV5Q11-06C6L2 VQ1100-5 VQ1200-5 VQ1300-5 VVQ1000-10A-1 Dust-proof IP65 W VQ2000 1 2 1 setManifold base No. 2 setsValve No. (Stations 1 to 2) 2 setsValve No. (Stations 3 to 4) 1 setValve No. (Station 5) 1 setBlank plate No. (Station 6) VQ1000 Note) VQ2000 only.
stepper motor 5 phase stepper motor 2 5 Number of auto/proximity switches Ball screw B Lead screw type 1 2 1 pc. 2 pcs.
When the number of generated alarms exceeds the maximum alarm output of each mode, it is deleted from the history in order of the alarm code generated in the past Ex) When the alarm is generated in order of (1)(5) 7 to 0 Alarm 1 Alarm 1 7 F to 8 Alarm 2 Alarm 2 7 to 0 Alarm 3 Alarm 1 (latest) (1) (2) (3) (4) (5) Alarm 2 0 (1) (2) (3) (4) 8 Alarm 3 0 0 (1) (2) (3) Alarm 4 0 0 0 (1) (2) F to
5 5 5 M6 x 1 M6 x 1 M8 x 1.25 M8 x 1.25 M10 x 1.5 M10 x 1.5 6 6 7 7 10 10 M10 x 1.25 M14 x 1.5 M18 x 1.5 M18 x 1.5 M22 x 1.5 M26 x 1.5 27 27 31.5 31.5 38 38 1/8 1/4 1/4 3/8 3/8 1/2 84 84 94 94 114 114 4 4 5 9 11.5 17 6.5 9 10.5 12 14 15 135 139 156 156 190 190 to 500 to 500 to 600 to 600 to 800 to 800 to 1000 50 223 97 15 17 120 1/2 38 M27 x 2 13 M12 x 1.75 6 20 19 27 60 32 110 136 54 19.5
4-28UNF depth 0.47 5/16-24UNF depth 0.63 3/8-24UNF depth 0.63 1/8 1/8 1/8 1/8 1/4 1/4 1/4-28UNF 5/16-24UNF 7/16-20UNF 7/16-20UNF 1/2-20UNF 1/2-20UNF 2.72 (3.03) 2.72 (3.03) 2.80 (3.11) 3.07 (3.38) 3.54 (3.85) 3.54 (3.85) 0.43 0.43 0.43 0.47 0.51 0.51 0.43 0.43 0.39 (0.43) 0.39 (0.47) 0.47 (0.51) 0.47 (0.51) 3.80 (4.11) 3.92 (4.23) 4.51 (4.82) 4.78 (5.13) 5.69 (6.16) 5.69 (6.16) 0.94 1.14
B M5 x 0.8 M4 xO.7 5-30 '11 20 32 2 6 7 8 1 7 2A 1 6 . 5 1 9 M5 x 0-8 N45 x 0.8 5-50 1 4 26 40 3 8 I 8 20 1 9 21.5 M5 x 0.8 N.45 x 0.8 5-50 t l ) . 5 1 8 32 50 4 1 0 1 0 1 0 20 22 43.5 22 1/8 (PT) 1i8 (PT) 5-50 1 9 5 22 40 5 1 l 1 2 24 29 5 1 . 5 22 23 i il : lModel I l ] H : H A L J KI L Mt\4 NA NB oP Q ] . , R i l : : S I sl L', . l Y r l lrye f Kqgq'l 26 5 1 4 M4 xO.7 5 M5 x 0.8 6 1 8