T1 = V/a1 = 300/5000 = 0.06 [s], T3 = V/a2 = 300/5000 = 0.06 [s] 300 0.5300(0.06 + 0.06) 300 T2 = = = 0.94 [s] L 0.5V(T1 + T3) V T4 = 0.05 [s] Therefore, the cycle time can be obtained as follows.
Your search for LEY25 returned 30 result(s)
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